Question

sin theta equals to half and Cos theta equals to minus root 3 upon 2 find the general solution​

Answer 1

Step-by-step explanation:

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cos θ = \frac{\sqrt{3} }{2}

2

3

sin θ = \frac{1}{2}

2

1

\frac{1 - sec theta}{1 + cosec theta}

1+cosectheta

1−sectheta

= \frac{\frac{1-2}{\sqrt{3} } }{1 + 2}

1+2

3

1−2

= \frac{\sqrt{3} -2 }{2}

2

3

−2

× \frac{1}{3}

3

1

= \frac{\sqrt{3} - 2}{6}

6

3

−2

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