Question

sin theta is a/b then cos theta.......​

Answer 1

Given sin theta = a/b =perpendicular/height

Then cos theta = ?

We know that ,

${h}^{2} = {b}^{2} + {p}^{2}$

B^2=√(b)^2-(a)^2

Cos theta= B/H= √(b)^2-(a)^2/b^2

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Answer 2

Answer:

cos theta =b/a

hope it works

Step-by-step explanation: