sin theta minus cos theta equals to zero then what is the value of the expression sin to the power 6 theta + cos to the power 6 theta
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Answer:
1/4
Step-by-step explanation:
let theta = alpha = ∝
sin theta minus cos theta equals to zero
sin∝ - cos∝ = 0
sin∧6∝ + cos∧6∝
= (sin²∝ + cos²∝ ) ( sin∧4∝ + cos∧4∝ - sin²∝ cos²∝ )
= sin∧4∝ + cos∧4∝ - sin²∝ cos²∝
= sin∧4∝ + cos∧4∝ + 2 sin²∝ cos²∝ - 3 sin²∝ cos²∝
= (sin²∝ + cos²∝ )² - 3 sin²∝ cos²∝
= 1 - 3 sin²∝ cos²∝
= 1 - 3 sin∧4∝
= 1 - 3/4
= 1/4
I hope this will help you...
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