sin theta * sin theta + cos theta * cos theta = 1 prove it
Answers
Answered by
1
sin theta*sin theta + cos theta*cos theta
sin^2 theta+cos^2theta
and by the identity = sin^2theta+cos^2theta=1
we can get the proving part that is 1
sin^2 theta+cos^2theta
and by the identity = sin^2theta+cos^2theta=1
we can get the proving part that is 1
Answered by
3
Lets take a right angled triangle having sides 1 and 1.
Let a and b are the two sides.
So the third side, using Pythagorus Theorem,
c² = a² + b² = 1² + 1² = 2
c = √2 units
Let theta be an angle (other than the right angle) in the triangle...
sine theta = opp/hyp = 1 /√2
So, sine² theta = 1/2
cosine² theta = adj/hyp = 1 /√2
So, cosine² theta = 1/2
Therefore,
sine² theta + cosine² theta = (1/2) + (1/2) = 1.
Hence, proved.
-WonderGirl
Let a and b are the two sides.
So the third side, using Pythagorus Theorem,
c² = a² + b² = 1² + 1² = 2
c = √2 units
Let theta be an angle (other than the right angle) in the triangle...
sine theta = opp/hyp = 1 /√2
So, sine² theta = 1/2
cosine² theta = adj/hyp = 1 /√2
So, cosine² theta = 1/2
Therefore,
sine² theta + cosine² theta = (1/2) + (1/2) = 1.
Hence, proved.
-WonderGirl
Similar questions