Sin theta upon 1 minus cos theta equal to 1 + cos theta upon sin theta proof
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Acc. to me,
suppose it is theta---Ф
sinФ/1-cosФ=1+cosФ/sinФ
just rationalise on LHS by (1+cosФ)
LHS is
=sinФ(1+cosФ)/(1-cosФ)(1+cosФ)
=sinФ(1+cosФ)/1²-cos²Ф------[becz(a+b)(a-b)=a²-b²
and 1-cos²Ф=sin²Ф]
=sinФ(1+cosФ)/sin²Ф
[sinФ cut one sinФ from denominator and]
=1+cosФ/sinФ---that is RHS
I Hope it help
any problem ask
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