sin theta upon root 1 minus sin square theta into cos theta upon root 1 + cot square theta is equal to
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the answer of your question is
sin^2 theta
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Answer:
Step-by-step explanation:
SinA/√1-sin^2 A × cosA/√ 1+cot^2A
SinA/ √(1) ^2-(sinA) ^2 × cosA/√(1) ^2+(cotA) ^2
SinA/1- SinA× CosA / 1+CotA
SinA/1- SinA× SinA. CosA/ SinA+ CosA
Sin^2A.CosA/1+CosA- SinA- SinACosA
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