Question

(sin thetha-cos thetha)^=1-sin 2 thetha​

Answer 1

Step-by-step explanation:

sin(-x) = -sin(x)

csc(-x) = -csc(x)

cos(-x) = cos(x)

sec(-x) = sec(x)

tan(-x) = -tan(x)

cot(-x) = -cot(x)

sin^2(x) + cos^2(x) = 1

tan^2(x) + 1 = sec^2(x)

cot^2(x) + 1 = csc^2(x)

sin(x y) = sin x cos y cos x sin y

cos(x y) = cos x cosy sin x sin y

tan(x y) = (tan x tan y) / (1 tan x tan y)

sin(2x) = 2 sin x cos x

cos(2x) = cos^2(x) - sin^2(x) = 2 cos^2(x) - 1 = 1 - 2 sin^2(x)

tan(2x) = 2 tan(x) / (1 - tan^2(x))

sin^2(x) = 1/2 - 1/2 cos(2x)

cos^2(x) = 1/2 + 1/2 cos(2x)

sin x - sin y = 2 sin( (x - y)/2 ) cos( (x + y)/2 )

cos x - cos y = -2 sin( (x - y)/2 ) sin( (x + y)/2 )

Trig Table of Common Angles

angle 0 30 45 60 90

sin^2(a) 0/4 1/4 2/4 3/4 4/4

cos^2(a) 4/4 3/4 2/4 1/4 0/4

tan^2(a) 0/4 1/3 2/2 3/1 4/0