Question

sin thita+cos thita /
sin thita - cos thita
+ sin thita -cos thita/
Sin thita + cos thita= 2/sin2-1​

Answer 1

Step-by-step explanation:

what is it.................

Answer 2

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Given : sinα -cosα /sinα +cosα +sin α +cosα/sin α -cos α =2/2sin²-1

L.H.S.

Take L.C.M.

⇒[( sinα -cosα)²+ ( sinα +cosα)²]/[( sinα -cosα)( sinα +cosα)]

⇒2(sin²α+cos²α) /(sin²α-cos²α) [ ∵ (a+b)²+(a-b)²= 2(a²+b²)]

⇒2/(cos 2α) [ ∵ sin²α-cos²α=cos 2α]

⇒2/ 2sin²α-1 [ ∵ cos 2α= 2sin²α-1 ]

L.H.S.=R.H.S.