Math, asked by champasaha57gmailcom, 10 months ago

sin thita + sin 3thita+ sin 5thita+ sin 7thita/cos thita + cos 3thita + cos 5thita + cos 7thita=tan 4thita​

Answers

Answered by Anonymous
1

(sintheta+sin3theta+sin5theta+sin7theta)/(costheta+cos3theta+cos5theta+cos7theta),

={(sin7theta+sintheta)+(sin5theta+sin3theta)}/{(cos7theta+costheta)+(cos5theta+cos3theta)},

={(2sin4thetacos3theta)+(2sin4thetacostheta)}/{(2cos4thetacos3theta)+(2cos4thetacostheta)},

={cancel2sin4thetacancel((cos3theta+costheta))}/{cancel2cos4thetacancel((cos3theta+costheta))},

=sin 4 θ /cos4 θ

, =tan4theeta

 

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