Math, asked by vanshchoudhary57, 1 year ago

sin^=x anx sec^ =y , find value of cot^=?

Answers

Answered by rani1928

2

sin^= x

sec^=y..... 1/cos^=y.....cos^=1/y

cot^=cos^/sin^

cot^= 1/y/x

cot^=1/xy......ans

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