Question

sin x =cos y,, cosec (X+Y)=?​

Answer 1

Answer:

1

Step-by-step explanation:

${ \sin(x) }^{2} = { \cos(y) }^{2} \\ \\ { \sin(x) }^{2} + { \sin(y) }^{2} = 1 = { \sin(x) }^{2} + { \cos(x) }^{2} \\ \sin(y) = \cos(x)$

sinx.Siny= cosx.cosy

cosx.cosy- sinx.siny = 0

cos(x+y)=0

1-sin^2(x+y)=0

sin^2(X+Y)=1

sin(X+Y)=1

cosec(x+y)=1

Hope it will help.