Math, asked by 919392384173, 1 month ago

sin x+sin y=3(cos y-cos x) then sin3x/sin3y​=

Answers

Answered by shreyashmate555
0

Step-by-step explanation:

sinx+siny=3cosy−3cosx

10

1

sinx+

10

3

cosx=

10

−1

siny+

10

3

cosy

sinα=3/

10

cosα=1/

10

sinxcosα+sinαcosx=sinαcosy−cosαsiny

sin(x+α)=sin(α−y)

⇒x+α=α−y⇒x=−y

sin3y

sin3x

=

sin3y

sin(−3y)

=

sin3y

−sin3y

=−1

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