Sin x +sin y=a and cos x + cos y =b find tan (x+y/2)
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Sin x +sin y=a <=> 2sin[(x+y)/2].cos[(x-y)/2] = a
cos x + cos y =b <=> 2cos[(x+y)/2].cos[(x-y)/2] = b
Take : 2sin[(x+y)/2].cos[(x-y)/2] divide 2cos[(x+y)/2].cos[(x-y)/2], the result is : tan[(x+y)/2] = a/b
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