Question

sin°/1-cos°=1+cos°/sin°=cosec°+cot° plz fast

Answer 1

Answer:

1.

sin°/1-cos° = 1+cos°/sin°

sin^2∆ = (1+ cos°) × (1- cos°)

sin^2∆ = 1^2 - cos^2

【 sin^2∆ = sin^2 ∆】

2.

1+cos°/sin° = cosec°+cot°

1+cos°/sin°= 1/sin° + cos°/sin°

【1 + cos°/sin° = cosec° + cot° 】

° . ° Proved

Hope it helps you..✌️✌️

Answer 2

sin A / (1-cos A) -------> (1)

(Multiplying and Dividing with (1+cos A) )

sin A (1+cos A) /(1-cos A)(1+cos A)

(sin A + sin A • cos A) / (1-cos² A)

(sin A + sin A • cos A) / sin² A

(sin A/sin² A) + (sin A • cos A / sin² A)

(1/sin A) + (cos A / sin A)

(1+cos A)/ sin A -----> (2)

(1/sin A) + (cos A / sin A)

= cosec A + cot A ------> (3)

So, we proved (1) = (2) = (3)

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