sin0=4/5 then cosec0/1+cot0=?
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sin=4/5= p/h
by pythogaras
5^2=4^2+b^2
25=16+ b^2
b^2= 9
b= 3
now
cosec0/1+cot0=5/4+3/4=8/8=1
by pythogaras
5^2=4^2+b^2
25=16+ b^2
b^2= 9
b= 3
now
cosec0/1+cot0=5/4+3/4=8/8=1
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