sin105 + cos105=cos45
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Answered by
54
sin105+cos105= cos45
sin(60+45)+cos(60+45)=1/√2
sin60cos45+cos60sin45+
cos60cos45-sin60sin45= 1/√2
√3/2 *1/√2 + 1/2 * 1/√2 + 1/2 * 1/√2 - √3/2 * 1/√2 = 1/√2
1/2√2 + 1/2√2= 1/√2
2/2√2= 1/√2
1/√2= 1/√2 ans
sin(60+45)+cos(60+45)=1/√2
sin60cos45+cos60sin45+
cos60cos45-sin60sin45= 1/√2
√3/2 *1/√2 + 1/2 * 1/√2 + 1/2 * 1/√2 - √3/2 * 1/√2 = 1/√2
1/2√2 + 1/2√2= 1/√2
2/2√2= 1/√2
1/√2= 1/√2 ans
Answered by
38
Hi ,
LHS = sin 105 + cos105
= Sin( 60 + 45 ) + cos ( 60 + 45 )
= ( sin60cos45+sin45cos60 ) +
( cos60cos45 - sin60sin45 )
= ( √3/2 ) ( 1/√2 ) + ( 1/√2 ) ( 1/2 ) + ( 1/2 ) ( 1/√2 ) - ( √3/2 ) ( 1/√2 )
= ( √3/2√2 ) + ( 1/2√2 ) + (1/2√2 ) - (√3/2√2 )
= 2/2√2
= 1/√2
= Cos45°
= RHS
I hope this helps you.
:)
LHS = sin 105 + cos105
= Sin( 60 + 45 ) + cos ( 60 + 45 )
= ( sin60cos45+sin45cos60 ) +
( cos60cos45 - sin60sin45 )
= ( √3/2 ) ( 1/√2 ) + ( 1/√2 ) ( 1/2 ) + ( 1/2 ) ( 1/√2 ) - ( √3/2 ) ( 1/√2 )
= ( √3/2√2 ) + ( 1/2√2 ) + (1/2√2 ) - (√3/2√2 )
= 2/2√2
= 1/√2
= Cos45°
= RHS
I hope this helps you.
:)
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