Question

sin10sin50sin60sin70=root 3/16. prove

Answer 1

This is a very interesting question!

sin10sin50sin60sin70
= [(√3)/2]sin10sin50sin70
= [(√3)/2]sin10(cos(-20) - cos120)/2
= [(√3)/2]sin10(cos20 - cos120)/2
= [(√3)/2](sin10cos20 - sin10cos120)/2
= [(√3)/2](sin30 + sin(-10) - 2sin10cos120)/4
= [(√3)/2](sin30 + sin(-10) + sin10)/4
= [(√3)/2](1/2)/4
= (√3)/16

Hope it helps!!!

Answer 2

Answer:

Step-by-step explanation:

sin10sin50sin60sin70

= [(√3)/2]sin10sin50sin70

= [(√3)/2]sin10(cos(-20) - cos120)/2

= [(√3)/2]sin10(cos20 - cos120)/2

= [(√3)/2](sin10cos20 - sin10cos120)/2

= [(√3)/2](sin30 + sin(-10) - 2sin10cos120)/4

= [(√3)/2](sin30 + sin(-10) + sin10)/4

= [(√3)/2](1/2)/4

= (√3)/16