Question

sin15 degree. cos15 degree​

Answer 1

Step-by-step explanation:

Apply, sin ( a-b) ×cos(a-b)

sin (60°-45°)×cos(60°-45°)

=(sin 60°×cos45°-cos60°×sin45°)(cos60°×cos45°+sin60°×sin45°)

=(√3/2×1/2-1/2×1/√2)(1/2×1/√2+√3/2×1/√2)

={(√3-1)/2√2×(√3+1)/2√2}

=(√3)^2-1^2/2√2×2√2

=3-1/4×2

=2/8

=1/4

Answer=1/4

Hope you understand this