Question

sin2 63°+sin2 27°/cos2 17°+cos2 73°​

Answer 1

Answer:

sin²A = cos²(90 - A)

sin²A + cos²A = 1

(sin²63 + sin²27)/(cos²17 + cos²73)

=( sin²63 + cos²63)/(cos²17 + sin²17)

= 1/1

= 1