sin²Φsec²Φ-sec²Φ=? ans plzzz
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Answered by
1
sin²x*sec²x = sin²x/cos²x = tan²x
Putting the value in given equation
= tan²x - sec²x
= -(sec²x - tan²x)
= -1 (by formula sec²x - tan²x = 1)
Putting the value in given equation
= tan²x - sec²x
= -(sec²x - tan²x)
= -1 (by formula sec²x - tan²x = 1)
Answered by
1
sin²A sec²A– sec²A
→sin²A.1/cos²A – sec²A
→sin²A/cos²A – sec²A
→tan²A – sec²A = -1
I used A instead of theta.
→sin²A.1/cos²A – sec²A
→sin²A/cos²A – sec²A
→tan²A – sec²A = -1
I used A instead of theta.
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