Question

sin2 thita +cos2 thita​

Answer 1

Answer:

sin2thita+cos2thita

= 1

(it is an identity)

Answer 2

Answer:

$Here's an alternate answer. Recall the identity sin2θ+cos2θ=1. If you rearrange for cos2θ, you should get cos2θ=1−sin2θ.</p><p></p><p>Substituting, we have:</p><p></p><p>sin2θ−(1−sin2θ)=0</p><p></p><p>sin2θ−1+sin2θ=0</p><p></p><p>2sin2θ=1</p><p></p><p>sin2θ=12</p><p></p><p>sinθ=±1√2</p><p></p><p>Now consider the 1−1−√2 right triangle. This means that</p><p></p><p>θ=π4+2πn,3π4+2πn,5π4+2πnand7π4+2πn</p><p></p><p>Note the period of the sine function is 2π.</p><p></p><p>Hopefully this helps!</p><p></p><p>$

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