Math, asked by anushkaks, 6 months ago

Sin20/cos70 + cos20/sin70 +tan20tan70

Answers

Answered by pdhankhar2006
0

Answer:

Step-by-step explanation:

sin 20°/cos 70° + cos 20°/sin 70° + tan 20° X tan 70°

sin (90° - 70°)/cos 70° + cos (90° - 70°)/sin 70° + tan (90° - 70°) X tan 70°

cos 70°/cos 70° + sin 70°/sin 70° + cot 70° X tan 70°

1 + 1 + (1/tan 70° X tan 70°)

2 + 1

3

Answered by SujalSirimilla
0

Answer:

\frac{Sin20}{Cos70} +\frac{Cos20}{Sin70}+ Tan20*Tan70.....(a)

We know that:

  1. Sin20=cos(90-20)=cos(70)
  2. Cos20=sin(90-20)=sin(70)
  3. Tan20=cot(90-20)=cot(70)

Substitute 1., 2. and 3. in (a):

\frac{Cos70}{Cos70} +\frac{Sin70}{Sin70}+ cot70*Tan70

We know that cot∅*tan∅=1

Thus, cot70*tan70=1.

\frac{Cos70}{Cos70} +\frac{Sin70}{Sin70}+ cot70*Tan70=1+1+1=3

Thus 3 is your answer.

HOPE THIS HELPS :D

Similar questions