Question

SIN20°COS70°+COS20°SIN70°

Answer 1

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Answer 2

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QUESTION :)




SIN20°COS70°+COS20°SIN70°


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ANSWERS :)



tg (90_x) =tgx = 1_
yg

sin (90-x) = cos

sin2 ×+ cos× =1

LIC2YMY


SIN 20 COS 70 + COS 20 SIN 70_ TG 10 TG 80


=SIN 20 COS (90-20)+ COS 20 SIN (90-20) -G

10 TG (90-10)



= ✔✔✅SIN2 20 + COS 20 _tg 10 = 1 / tg 10 = 1-1===0

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