sin²45+cos²60+sin²30+cosec 45*sec 45
solve with full working formula and reasoning
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is it your answer 2/3.
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divyansh101dabral:
thanks
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In LHS
sin²45+cos²60+sin²30+cosec45×sec45(so,sin45=1/√2,cos60=0,sin30=1/2,cosec45=√2 and sec45=√2)
puting the values
=(1/√2)²+(0)²+(1/2)²+√2×√2
=1/2+0+1/4+2
=2+1+4/4
=7/4
=1.75
sin²45+cos²60+sin²30+cosec45×sec45(so,sin45=1/√2,cos60=0,sin30=1/2,cosec45=√2 and sec45=√2)
puting the values
=(1/√2)²+(0)²+(1/2)²+√2×√2
=1/2+0+1/4+2
=2+1+4/4
=7/4
=1.75
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