Math, asked by adhaliwal333, 20 days ago

Sin25^°/cos35^°-cos25^°/sim35^°

Answers

Answered by pragyabundiwal59

0

Step-by-step explanation:

$use \: rule$

$\cos( \alpha + \beta ) = \cos \alpha \cos \beta - \sin\alpha \sin \beta$

$\sin2 \ \beta = 2 \sin \beta \cos \beta$

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