Question

sin²60-tan45+cos²30-cot90 please give me solution and Answer ​

Answer 1

Answer:

U can see all trigonometry values in attachment.

$\huge \sf { \underline{ \red{Question}}}$

${ \sf {sin}^{2} 60 - tan45 + {cos}^{2} 30 - cot90}$

Solution:-

$= { \sf{ {sin}^{2} 60 - tan45 + {cos}^{2} 30 - cot90}}$

$= { (\frac{ \sqrt{3} }{2}) }^{2} - 1 + { (\frac{ \sqrt{3} }{2}) }^{2} - 0$

$= \frac{3}{4} - 1 + \frac{3}{4} - 0$

$= \frac{6}{4} - 1$

$= \frac{2}{4}$

$= \frac{1}{2}$

Therefore,

${ \sf{ {sin}^{2} 60 - tan45 + {cos}^{2} 30 - cot90 = \frac{1}{2} }}$

Answer 2

Answer:

1/2 is answer..................