Math, asked by Anonymous, 9 months ago

sin²A cos²B + cos²A sin² B + sin²A sin² B + cos² A cos² B =

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Answered by sandy1816

3

Answer:

your answer attached in the photo

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Answered by Anonymous

3

Answer:

sin ^ A cos ^ B + cos ^ A sin ^ B + sin ^ A sin ^ B + cos^ A cos ^ B

sin ^ A ( cos ^B + sin ^ B ) + cos^A ( sin ^ B + cos^ B )

sin ^ A + cos ^ A

= 1

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