sin²A cos²B + cos²A sin² B + sin²A sin² B + cos² A cos² B =
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3
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Answered by
3
Answer:
sin ^ A cos ^ B + cos ^ A sin ^ B + sin ^ A sin ^ B + cos^ A cos ^ B
sin ^ A ( cos ^B + sin ^ B ) + cos^A ( sin ^ B + cos^ B )
sin ^ A + cos ^ A
= 1
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