Question

Sin2A ka formula
Sin3A
Cos2A
Cos3A
​

Answer 1

Answer:

sin2A = 2sinAcosA

sin3A = 3sinA - 4sin^3A

cos2A = cos^2A - sin^2A

cos3A = 4cos^3A - 3cosA

Answer 2

Answer:

Sin 2A :

2SinA. CosA

Sin 3A:

3sinA-4sin^3A

Cos 2A:

• Cos^2A - Sin^2A
• 2cos^2A-1
• 1-2Sin^2A

Cos 3A:

4Cos^3A-3CosA

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