Question

sin²A-sin²B=sin(A+B)sin(A-B)​

Answer 1

Step-by-step explanation:

sin²A-sin²B=sin[(A+B)(A-B)]

sin²A-sin²B=sin[A²-B²]

sin²A-sin²B=sin²A-sin²B

I hope this will help you

please mark me as brainlist

Answer 2

Answer:

refer to the attachment for the solution.

if it helps you then Mark as brainliest.