Math, asked by dheerajkalsi4655, 1 year ago

sin2A+sin2B/sin2A-sin2B=tan(A+B)/tan(A-B)

Answers

Answered by seem1512
115
sin 2A + sin 2B = 2sin(A+B) cos(A-B) 
sin 2A - sin 2B = 2cos(A+B)sin(A-B) 

dividing both... 

(2sin(A+B) cos(A-B)) / (2cos(A+B)sin(A-B)) 
= (sin(A+B)cos(A-B))/(cos(A+B)sin(A-B)) 
=tan(A+B) X cot(A-B) 
=tan (A+B) / tan(A-B)
Answered by siddhmohanty1023
25

Step-by-step explanation:

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