Question

sin2A+sin2B/sin2A-sin2B = tan(A+B)/tan(A-B) prove that

Answer 1

for l.h.s:
take transformations..
sinA+sinB=2sin(a+b/2)cos(a-b/2)
sinA-sinB=2cos(a+b/2)sin(a-b/2)

for r.h.s:
write tan as sin/cos and simplify..you're done