Question

sin2Acos2B+cos2Asin2B+cos2Acos2B+sin2Asin2B=1​

Answer 1

$\huge\star{\bold{\underline{\red{\mid{Answer}}}}}\star$

$\large\bigcirc{\underline{\green{\mathscr{Trigonometry}}}}\bigcirc$

___________________________

$\implies$sin²Acos²B+cos²Asin²B+cos²Acos²B+sin²Asin²B

$\implies$sin²A(cos²B+sin²B)+cos²A(sin²B+cos²B)

$\implies$sin²A(1)+cos²A(1)

$\implies$sin²A+cos²B

$\huge\implies$1

___________________________