Question

sin³(180⁰+A).tan(360⁰-A).sec²(180⁰-A)/cos²(90⁰+A).cosec²A.sin(180⁰-A)=tan³A

Answer 1

Answer:

show that sin3(180+A) tan(360-A) sec2(180-A) / cos2(90+A)cosec2A sin(180-A) = tan3A

Answer 2

Answer:

See the attachment for the answer.

Hope this helps you!

Step-by-step explanation: