sin³(180⁰+A).tan(360⁰-A).sec²(180⁰-A)/cos²(90⁰+A).cosec²A.sin(180⁰-A)=tan³A
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show that sin3(180+A) tan(360-A) sec2(180-A) / cos2(90+A)cosec2A sin(180-A) = tan3A
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