Question

Sin30+tan45-cosec60/sec30+cos60+cot45

Answer 1

substitute the value. 
sin30+tan45-cosec60/sec30+ cos60+ cot45= 1/2 + 1 -(2/sqr3)/(2sqrt3) + 1/2 +1 
= 1/2 + 1- 1 +1/2 +1 
= 1/2 + 1/2 + 2/2 (making denominators same) 
= 4/2 = 2 
Answer: 2

Answer 2

Answer: your answer is $3\sqrt{3}-4/4+3\sqrt{3}$

Explanation:

$1/2+1-2\sqrt{3}/2\sqrt{3} whole divided by 2\sqrt{3} +1/2+1$4

$3/2-2\sqrt{3}-whole-divided-by-2/\sqrt{3}+3/2$

$\sqrt[3]{3}-4/\sqrt[2]{3}/4-whole-divided-by-4+\sqrt[3]{3}/2\sqrt{3}$$\sqrt[3]{3}-4/\sqrt[2]{3}*\sqrt[2]{3}/4+\sqrt[3]{3}$

$\sqrt[3]{3}-4/4+\sqrt[3]{3}$