Sin300.cos120+cos210.sin300
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The formula for
sin (A+B)= sinAcosB + cosAsinB
In the question we have
sin300.cos120 + cos300.sin120
=sin (300+120)
=sin(420)
=sin(360+60)
=sin60
=√3/2
Hope it helps ...... :-)
sin (A+B)= sinAcosB + cosAsinB
In the question we have
sin300.cos120 + cos300.sin120
=sin (300+120)
=sin(420)
=sin(360+60)
=sin60
=√3/2
Hope it helps ...... :-)
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