Sin32/cos 58 + sin 22 /cos 48 - cos 48. cosec 42/tan28 . tan 25 . tan 30 . tan 62 . tan 65
Answers
Step-by-step explanation:
i hope my answer will be helpful for you
Given : Sin32/cos 58 + sin 22 /cos 68 - cos 48. cosec 42/tan28 . tan 25 . tan 30 . tan 62 . tan 65
To Find : Value :
Solution:
Sin32/cos 58 + sin 22 /cos 68 - cos 48. cosec 42/tan28 . tan 25 . tan 30 . tan 62 . tan 65
cos 58 = Sin(90-58) = Sin32
=> Sin32/cos 58 = 1
cos 68 = Sin(90-68) = Sin22
=> Sin22/cos 68 = 1
cosec 42 = 1/Sin42 = 1/Cos(90 - 42) = 1/Cos48
=> cos 48. cosec 42 = 1
tan 62 = Cot(90 - 62) = Cot28 = 1/tan28
tan 65 = Cot(90 - 65) = Cot25= 1/tan25
=> tan28 . tan 25 . tan 30 . tan 62 . tan 65 =tan28 . tan 25 . tan 30 ./ tan28 . tan 25
= tan30
= 1/√3
Sin32/cos 58 + sin 22 /cos 68 - cos 48. cosec 42/tan28 . tan 25 . tan 30 . tan 62 . tan 65
= 1 + 1 - 1/√3
= 2 - 1/√3
= 2 - √3/3
= (6 - √3)/3
Learn More:
cot(-405°) + cot (495°) tan (-585°)
https://brainly.in/question/10973642
cosec(90-x)+tan(180-x)+
https://brainly.in/question/10433206