Question

sin³43-sin³17/sin43-sin17​

Answer 1

Answer:

Step-by-step explanation:

Since

$a^{3}-b^{3} = (a-b)(a^{2}+b^{2}+ab)\\Given that \frac{Sin^{3}43-Sin^{3}17 }{Sin43-Sin17 }\\\\= \frac{(Sin43-Sin17)(Sin^{2}43+Sin^{2}17+Sin43Sin17) }{(Sin43-Sin17)} \\\\= Sin^{2}43+Sin^{2}17+Sin43Sin17$