sin3A = cos(A-26) where A is an acute angle. Find the value of A
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sin3A= cos(A-26)
=> cos(90-3A) = cos(A-26)
=> 90-3A =A-26
=> 90+26= A+3A
=> 4A= 116
=> A= 116/4 = 29°
=> cos(90-3A) = cos(A-26)
=> 90-3A =A-26
=> 90+26= A+3A
=> 4A= 116
=> A= 116/4 = 29°
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