Math, asked by ladaryan18, 11 months ago

sin3a/sina+cos3a/cosa=4cos^2a

Answers

Answered by sandy1816
3

Step-by-step explanation:

sin3a/sina+cos3a/cosa

=sin3acosa+cos3asina/sinacosa

=sin(3a+a)/sinacosa

=sin4a/sinacosa

=sin2.2a/sinacosa

=2sin2acos2a/sinacosa

multiplied by 2 in both numerator & denominator

2(2sin2acos2a)/2sinacosa

=2(2sin2acos2a)/sin2a

=2.2cos2a

=4cos2a

thankyou

Answered by shashank25shri
0

Answer:

I hope it will help you.

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