sin³o + cos³o/ sin o+cos o + sin o cos o =1
Answers
Answered by
18
Step-by-step explanation:
LHS=
1−sinA
cosA
+
1+sinA
cosA
=
(1−sin
2
A)
cosA(1+sinA+1−sinA)
=
cos
2
A
2cosA
=
cosA
2
=2secA=RHS
Hence proved.
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