Math, asked by gudiyabharadwaj75, 6 months ago

sin³o + cos³o/ sin o+cos o + sin o cos o =1​

Answers

Answered by Anonymous
18

Step-by-step explanation:

LHS=

1−sinA

cosA

+

1+sinA

cosA

=

(1−sin

2

A)

cosA(1+sinA+1−sinA)

=

cos

2

A

2cosA

=

cosA

2

=2secA=RHS

Hence proved.

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