Question

(sin³theta+sin3theta)/(cos³theta-cos3theta)​

Answer 1

Answer:

1 is the answer i think soooo

Answer 2

Answer:

$\frac{sin^3\theta + sin3\theta}{cos^3\theta - cos3\theta}$ = cot$\theta$

Step-by-step explanation:  

Formulas:___________________________________

sin3$\theta$ = 3sin$\theta$ - 4sin³$\theta$

cos3$\theta$ = 4cos³$\theta$ - 3cos$\theta$---------------------------------------------------------------------------------

$\frac{sin^3\theta + sin3\theta}{cos^3\theta - cos3\theta}$

= $\frac{sin^3\theta + 3sin\theta - 4 sin^3\theta}{cos^3\theta - (4cos^3\theta-3cos\theta)}$  

= $\frac{3sin\theta - 3sin^3\theta}{3cos\theta-3cos^3\theta}$

= $\frac{3sin\theta (1 - sin^2\theta)}{3cos\theta (1 - cos^2\theta)}$

= $\frac{3sin\theta * cos^2\theta}{3cos\theta*sin^2\theta}$

= $\frac{cos\theta}{sin\theta}$

= cot$\theta$