Question

sin3x=cos(x-6°) where 3x & (x-6°) ate acute angles then find value of x.

Answer 1

$\bold{\boxed{HEY!!!}}$

Here is your answer :-

sin3x° = cos ( x - 6 )°

=> cos( 90 - 3x ) ° = cos ( x - 6 )°

=> 90 - 3x = x - 6

=> 90 + 6 = 3x + x

=> 96 = 4x

=> x = 96/4

=> x = 24

$\bold{\boxed{x = 24 }}$

$<marquee>THANKS...$

Answer 2

here here here is your answer

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