Math, asked by dhruviparmar056, 9 months ago

sin407sin133+sin317sin223=1​

Answers

Answered by srisaisagarteja
3

Step-by-step explanation:

sin407 sin133

sin(360+47).sin(180-47)

sin47×sin47

sin317.sin223

sin(270+47)sin(270-47)

(-cos47)×(-cos47)

cos47×cos47

therefore sin407sin133+sin317sin223

=sin47.sin47+cos47.cos47

( WKT sinx.sinx+cosx.cost=1)

=1

hence proved

Similar questions