Question

sin43 =p then cos 43degree interms of p

Answer 1

$\huge{\mathcal{\underline{\green{SOLUTION}}}} </p><p>$

$cos \: 43^{\circ} = \sqrt{1 - {sin} \: {43^{\circ}} } = \sqrt{1 - {p}^{2} }$

$</p><p>\displaystyle\textcolor{orange}{Please \: Mark \: it \: Brainliest}$

Answer 2

Answer:

cos43∘=1−sin43∘=1−p2