Question

sin45". cos45°- sin300 is ______
please answer fast

Answer 1

Let me help you with this question.
Given that,
sin 45° . cos 45° - sin 300°
= (1 / √2) . (1 / √2) - sin 300° (∵sin 45° = cos 45° = 1 / √2)
= 1 / (√2 x √2) - sin (270° + 30°)   
= 1 / 2 - (- cos 30°)   [∵ sin (270° + ∅) = - cos ∅]
= 1 / 2 + cos 30° 
= 1 / 2 + √3 / 2  (∵ cos 30° = √3 / 2)
= (1 + √3) / 2 
which is the required answer.
Hope it will help you. Thanks.