Question

(Sin49/cos41)square+(cos41/sin49)square=1

Answer 1

Correct Question

→ (sin 49°/cos 41°)² + (cos 41°/sin 49°)² = 2

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To Prove

→ (sin 49°/cos 41°)² + (cos 41°/sin 49°)² = 2

Given

• sin 49° = cos(90° - 49°)

→ [cos(90° - 49°)/cos 41°]² + [cos 41°/{cos(90° - 49°}]²

→ [cos 41°/cos 41°]² + [cos 41°/cos 41°]²

→ 1² + 1² = 2 = R.H.S

Hence Proved

Answer 2

Question—

Prove (sin 49°/cos 41°)² + (cos 41°/sin 49°)² = 2

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$\bf\huge\boxed{Answer}$

To Prove—

(sin 49°/cos 41°)² + (cos 41°/sin 49°)² = 2

Proof—

We know that

sin 49° = cos(90° - 49°)

[cos(90° - 49°)/cos 41°]² + [cos 41°/{cos(90° - 49°}]²

[cos 41°/cos 41°]² + [cos 41°/cos 41°]²

=> 1² + 1² = 2 = R.H.S

Hence Proved

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