Sin49/cos41 square + cos41/sin49 square
Answers
Answered by
124
As we know that
sin(90°-α) = cosα
and, cos(90°-α) = sinα
∴(sin49°/cos41°)²+(cos41°/sin49°)²
=[sin(90°-41)/cos41°]² +[cos(90°-49°)/sin49°]²
=[cos41°/cos41°]² +[sin49°/sin49°]²
=1+1
=2
sin(90°-α) = cosα
and, cos(90°-α) = sinα
∴(sin49°/cos41°)²+(cos41°/sin49°)²
=[sin(90°-41)/cos41°]² +[cos(90°-49°)/sin49°]²
=[cos41°/cos41°]² +[sin49°/sin49°]²
=1+1
=2
Answered by
37
Answer:. 2
Step-by-step explanation:
sin49°/cos41°)²+(cos41°/sin49°)²
=[sin(90°-41)/cos41°]² +
[cos(90°-49°)/sin49°]²
=[cos41°/cos41°]² +[sin49°/sin49°]²
=1+1
=2
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