Sin4A_cos4A is equal to what
Answers
Answered by
1
Sin 4A - Cos 4A
= Sin 4A - Cos (90-4A)
= Sin 4A - Sin 4A
= 0
Answered by
1
Hey mate here is the answer of ur question;
cos⁴A = (cos²A)²
sin⁴A = (sin²A)²
cos⁴A - sin⁴A = (cos²A)² - (sin²A)²
= ( cos²A + sin²A) (cos²A - sin²A)
= (1)* (cos²A - (1 - cos²A)
= cos²A - 1 + cos²A
= 2 cos²A - 1
Hope it helps u mate!!
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DeadGuru:
hello
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