Math, asked by yashur242, 4 months ago

Sin⁴Q-cos⁴Q=1-2sin²Q

Answers

Answered by robinadogra1212

2

Step-by-step explanation:

(sin²Q-cos²Q)²=sin²Q+cos²Q-2sin²Q. (sin²Q+cos²Q=1)

(sin²Q-cos²Q)²=cos²Q-sin²Q

sin²Q-cos²Q=1

Answered by ekta1610

1

Answer:

I think you wrote wrong questions

but I Iam giving solution

Step-by-step explanation:

(cos²Q)²-(sin²Q)²

(sin²Q+cos²Q)(cos²Q-sin²Q)

1*(1-sin²Q-sin²Q)

1-2sin²Q

since LHS=RHS

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