Question

Sin⁴Q-cos⁴Q=1-2sin²Q​

Answer 1

Step-by-step explanation:

(sin²Q-cos²Q)²=sin²Q+cos²Q-2sin²Q. (sin²Q+cos²Q=1)

(sin²Q-cos²Q)²=cos²Q-sin²Q

sin²Q-cos²Q=1

Answer 2

Answer:

I think you wrote wrong questions

but I Iam giving solution

Step-by-step explanation:

(cos²Q)²-(sin²Q)²

(sin²Q+cos²Q)(cos²Q-sin²Q)

1*(1-sin²Q-sin²Q)

1-2sin²Q

since LHS=RHS