Question

Sin4theeta - cos4theeta/sin2theeta - cos2theeta

Answer 1

4ain theeta -4cos theeta/2sin theta-2coa theta 2×p/h -2×b/h

4×p/h-4×b/h / 2×p/h-2×b/h

4p/h-4b/h / 2p/h-2b/h

4p-4b/h / 2p-2b/h

h gets cancelled

so,4p-4b/2p-2b

4(p-b)/2(p-b)

4 gets divide by 2 and it remains 2

2p-2b